integer - Using == operator in Java to compare wrapper objects -

i'm reading scjp java 6 kathy sierra , bert bates , book confusing me much. on page 245 state following code below.

integer i1 = 1000; integer i2 = 1000; if(i1 != i2) system.out.println("different objects");  //prints output different objects 

then on next page have following code

integer i3 = 10; integer i4 = 10; if(i3 == i4) system.out.println("same objects");  //prints output same objects 

i'm confused! when try out on own seems cannot use == compare same way use equals() method. using == gives me 'false' if integer variables set same value (i.e. 10). correct? using == compare same integer object (with same values) result in 'false'

the key answer called object interning. java interns small numbers (less 128), instances of integer(n) n in interned range same. numbers greater or equal 128 not interned, hence integer(1000) objects not equal each other.