Java-Getting running file location of a child process -

hi have program executed jar file

public class maintestclass {      public static void main( string[] args ) throws ioexception, interruptedexception     {         process proc = runtime.getruntime().exec( "java -jar c:\\users\\rijo\\desktop\\test.jar" );         proc.waitfor();         java.io.inputstream = proc.getinputstream();         byte b[] = new byte[is.available()];         is.read( b, 0, b.length );         system.out.println( new string( b ) );     } } 

and test.jar definition :

public class testmain {     public static void main( string[] args )     {         system.out.println( "started" );         system.out.println( "path : " + new file( "" ).getabsolutepath() );         system.out.println( "end " );         system.out.println( system.getproperty( "user.dir" ) + " path" );     } } 

my intention running path of test.jar, test.jar executed maintestclass jar, system.getproperty( "user.dir" ) , new file( "" ).getabsolutepath() both returning maintestclass running path. there way child process running path inside test.jar itself.

you're confusing working directory (cwd) , basedir of running application (is call "running path"?). can run application inside cwd, java can use processbuilder:

string jar = "c:\\users\\rijo\\desktop\\test.jar"; process proc = new processbuilder()         .command("java", "-jar", jar)         .directory(new file(jar).getparentfile())         .start(); 

actually, should avoid depending on cwd, because user can run jar directory.