php - how to show record inserted successfully? -
<?php $id=$_session['id']; //$date1=date("y-m-d"); //echo $date1; $work=$_post['postinput0']; //echo $work; $project_name=$_post['postinput1']; $skills=$_post['postinput2']; $description=$_post['postinput3']; $file1=$_post['file1']; $budget=$_post['postinput4']; //$radio=$_post['radio']; $sql = "insert job_post (u_id,job_category,project_name,job_sub_category,project_description,image,budget) values('$id','$work','$project_name','$skills', '$description','$file1','$budget')"; if(mysql_query( $sql, $conn )) { echo "successfully"; } else { echo "not inserted"; } ?>
show message before submit button. dont want> plz me.
show message after submit button...... error in code
<?php if(isset($_post['submit'])) { $id=$_session['id']; //$date1=date("y-m-d"); //echo $date1; $work=$_post['postinput0']; //echo $work; $project_name=$_post['postinput1']; $skills=$_post['postinput2']; $description=$_post['postinput3']; $file1=$_post['file1']; $budget=$_post['postinput4']; //$radio=$_post['radio']; $sql = "insert job_post (u_id,job_category,project_name,job_sub_category,project_description,image,budget) values('$id','$work','$project_name','$skills', '$description','$file1','$budget')"; $query = mysql_query( $sql, $conn ); if(isset($query)) { echo "successfully"; } else { echo "not inserted"; } } ?>
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