Powershell & XML: Save data to a certain node of xml-file -

i have powershell script loads data xml. xml looks like:

<meta> <log>     <path>d:\logs\l1.log</path>     <lastwrite>01/30/2015 13:01:00</lastwrite>     <num>23</num> </log> <log>     <path>d:\log\l2.log</path>     <lastwrite>02/30/2015 14:02:00</lastwrite>     <num>67</num> </log> </meta> 

what change value in xml. first load data:

[xml]$xml = get-content "d:\config.xml" 

my problem is, how can address log-node in xml? i'm searching this:

$xml.meta.log.path | path = "d:\log\l2.log" 

and set new value , save xml-file.

maybe sb can me, have idea how search, i'm sure there's way. use ids within log-tags not solution, because have address nodes paths.

you there. instead of = use -eq condition. have use curly brackets , access current value using $_:

$xml.meta.log.path | { $_ -eq 'd:\log\l2.log' } 

alternative, can use where path query on $xml.meta.log , select path in additional statement:

$xml.meta.log | path -eq 'd:\log\l2.log' | select -expand path 

and here complete example modifies path , save xml back:

$configpath = 'd:\config.xml'  [xml]$xml = get-content $configpath  # select log log node path equals 'd:\log\l2.log'  $node = $xml.meta.log | path -eq 'd:\log\l2.log'   # set new path $node.path = 'd:\newlogpath\newlog.log'  # save xml $xml.save($configpath)