Understanding how to read nested lists in R in order to access the data -

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here set of list of lists of lists: please see development code read.genbank function here

#must connected internet work library(ape) library(plyr) gi_sample<-c(336087836, 336087835, 336087834) #use read.genbank function apply because have more max @ 1 time (400) my_output <- apply(gi_sample, 1, function(x) read.genbank(x))  str(my_output) list of 3  $ :list of 1   ..$ 336087836:class 'dnabin'  raw [1:606] 00 00 00 00 ...   ..- attr(*, "class")= chr "dnabin"   ..- attr(*, "species")= chr "flavobacterium_johnsoniae"   ..- attr(*, "references")=list of 1   .. ..$ 336087836:list of 2   .. .. ..$ :list of 4   .. .. .. ..$ pubmedid: chr(0)    .. .. .. ..$ authors : chr "rusznyak,a., akob,d.m., nietzsche,s., eusterhues,k., totsche,k.u., neu,t.r., frosch,t., popp,j., keiner,r., geletneky,j., katzs"| __truncated__   .. .. .. ..$ title   : chr "calcite mineralization karstic cave bacteria"   .. .. .. ..$ journal : chr "unpublished"   .. .. ..$ :list of 4   .. .. .. ..$ pubmedid: chr(0)    .. .. .. ..$ authors : chr "rusznyak,a."   .. .. .. ..$ title   : chr "direct submission"   .. .. .. ..$ journal : chr "submitted (13-apr-2011) insdc. institute of ecology, aquatic"  $ :list of 1   ..$ 336087835:class 'dnabin'  raw [1:991] 00 00 00 00 ...   ..- attr(*, "class")= chr "dnabin"   ..- attr(*, "species")= chr "rhodococcus_fascians"   ..- attr(*, "references")=list of 1   .. ..$ 336087835:list of 2   .. .. ..$ :list of 4   .. .. .. ..$ pubmedid: chr(0)    .. .. .. ..$ authors : chr "rusznyak,a., akob,d.m., nietzsche,s., eusterhues,k., totsche,k.u., neu,t.r., frosch,t., popp,j., keiner,r., geletneky,j., katzs"| __truncated__   .. .. .. ..$ title   : chr "calcite mineralization karstic cave bacteria"   .. .. .. ..$ journal : chr "unpublished"   .. .. ..$ :list of 4   .. .. .. ..$ pubmedid: chr(0)    .. .. .. ..$ authors : chr "rusznyak,a."   .. .. .. ..$ title   : chr "direct submission"   .. .. .. ..$ journal : chr "submitted (13-apr-2011) insdc. institute of ecology, aquatic"  $ :list of 1   ..$ 336087834:class 'dnabin'  raw [1:690] 00 00 00 00 ...   ..- attr(*, "class")= chr "dnabin"   ..- attr(*, "species")= chr "serratia_plymuthica"   ..- attr(*, "references")=list of 1   .. ..$ 336087834:list of 2   .. .. ..$ :list of 4   .. .. .. ..$ pubmedid: chr(0)    .. .. .. ..$ authors : chr "rusznyak,a., akob,d.m., nietzsche,s., eusterhues,k., totsche,k.u., neu,t.r., frosch,t., popp,j., keiner,r., geletneky,j., katzs"| __truncated__   .. .. .. ..$ title   : chr "calcite mineralization karstic cave bacteria"   .. .. .. ..$ journal : chr "unpublished"   .. .. ..$ :list of 4   .. .. .. ..$ pubmedid: chr(0)    .. .. .. ..$ authors : chr "rusznyak,a."   .. .. .. ..$ title   : chr "direct submission"   .. .. .. ..$ journal : chr "submitted (13-apr-2011) insdc. institute of ecology, aquatic"

what out of list: 

gi  authors     title       journal  336087836   "rusznyak,a., akob,d.m., nietzsche,s., eusterhues,k., totsche,k.u., neu,t.r., frosch,t., popp,j., keiner,r., geletneky,j., katzs"| __truncated__    "calcite mineralization karstic cave bacteria"   "unpublished" 336087835   "rusznyak,a., akob,d.m., nietzsche,s., eusterhues,k., totsche,k.u., neu,t.r., frosch,t., popp,j., keiner,r., geletneky,j., katzs"| __truncated__    "calcite mineralization karstic cave bacteria"   "unpublished" 336087834   "rusznyak,a., akob,d.m., nietzsche,s., eusterhues,k., totsche,k.u., neu,t.r., frosch,t., popp,j., keiner,r., geletneky,j., katzs"| __truncated__    "calcite mineralization karstic cave bacteria"   "unpublished"

i sorely in need of explanation of how these lists nested. how can access "title" , keep name of each list? have tinkered sorts of "[]" subsetting combinations , not understand how read list. have read many beginner explanations, , still @ loss.

this changed earlier question, although data remain same.

thank you!

it sounds dput of data hard have. build example might useful (just answer because long comment). 

a <- list(list(1:5), list(5:10)) b <- list(list(letters[1:5]), list(letters[5:10])) data.frame(unlist(a), unlist(b))    unlist.a. unlist.b. 1          1         2          2         b 3          3         c 4          4         d 5          5         e 6          5         e 7          6         f 8          7         g 9          8         h 10         9         11        10         j

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